9x^2-616x-2304=0

Solution for 9x^2-616x-2304=0 equation:

9x^2-616x-2304=0

a = 9; b = -616; c = -2304;
Δ = b2-4ac
Δ = -6162-4·9·(-2304)
Δ = 462400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{462400}=680$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-616)-680}{2*9}=\frac{-64}{18}
=-3+5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-616)+680}{2*9}=\frac{1296}{18}
=72
$